Asked by Elaine
How many milliters of 1.80M HCl are required to react with 30.0 grams of calcium hydroxide according to the given equation:
CA(OH)2(s) + 2HCl(aq)> CaCl2(aq) + 2H2O(l)
CA(OH)2(s) + 2HCl(aq)> CaCl2(aq) + 2H2O(l)
Answers
Answered by
DrBob222
moles Ca(OH)2 = M x L = ??
Using the coefficients in the balanced equation, convert moles Ca(OH)2 to moles HCl. (It will be 2 x moles Ca(OH)2).
Then M HCl = moles HCl/L HCl
Solve for L HCl and convert to mL.
Using the coefficients in the balanced equation, convert moles Ca(OH)2 to moles HCl. (It will be 2 x moles Ca(OH)2).
Then M HCl = moles HCl/L HCl
Solve for L HCl and convert to mL.
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