Asked by Anonymous
How many Milliters of 18.0M H2SO4 are required to react with 250mL of 2.50 M Al(OH)3 if the products are aluminum sulfate and water?
Answers
Answered by
DrBob222
Write the equation and balance it.
Calculate moles Al(OH)3. Moles = M x L.
Using the coefficients in the balanced equation, convert moles Al(OH)3 to moles H2SO4.
Then M H2SO4 = moles H2SO4/L H2SO4.
You know M and moles, calculate L H2SO4 and convert to mL.
Post your work if you get stuck.
Calculate moles Al(OH)3. Moles = M x L.
Using the coefficients in the balanced equation, convert moles Al(OH)3 to moles H2SO4.
Then M H2SO4 = moles H2SO4/L H2SO4.
You know M and moles, calculate L H2SO4 and convert to mL.
Post your work if you get stuck.
Answered by
Anonymous
Thanks!
Answered by
Getachew
How many millitres of 18.0MH2SO4 would be required to react with250Ml of 2.5Me Al(OH)3?
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