You must first solve for the theoretical yield and you do that the same way you did for the KClO3 example I gave you in your post just above. Then
%yield = (actual yield/theoretical yield)*100 = ??
A student reacts 20.0 grams of sodium hydroxide with hydrochloric acid and obtains 25.0 grams of sodium chloride. What is the percent yield?
2 answers
%CuS04.5H20
that Cu=63.5, S=32, 0(x9)=16*9=144 , H(*10)=1*10=10 that Cu+S+0+H=249,5 g
63.5/249.5*100%=25.5% what that is????
???
Actual Yield weight of copper after dry (g) ?????????
%cu= ????/
%Yield =Actual yield/theoretical Yield*100 ????????????/
That was experiment at school
that Cu=63.5, S=32, 0(x9)=16*9=144 , H(*10)=1*10=10 that Cu+S+0+H=249,5 g
63.5/249.5*100%=25.5% what that is????
???
Actual Yield weight of copper after dry (g) ?????????
%cu= ????/
%Yield =Actual yield/theoretical Yield*100 ????????????/
That was experiment at school
1 answer