2 grams of potassium (K) reacts with 5 grams of (O). According to the law of Conservation of Mass, how many grams of potassium oxide (K2O) will be produced?

Answer 1

To determine the mass of potassium oxide (K2O) produced, we first need to calculate the molar masses of potassium (K) and oxygen (O).

The molar mass of K is 39.10 g/mol, and the molar mass of O is 16.00 g/mol.

Since we're given the mass of K and O in grams, we can convert these masses to moles by dividing each mass by its respective molar mass:

moles of K = 2 g / (39.10 g/mol) = 0.051 mol
moles of O = 5 g / (16.00 g/mol) = 0.312 mol

From the balanced chemical equation of the reaction between K and O:
2K + O2 -> 2K2O

We can see that for every 2 moles of K, the reaction produces 2 moles of K2O.

Since we have 0.051 mol of K, we'll have the same number of moles of K2O produced:

moles of K2O = 0.051 mol

Finally, we can convert the moles of K2O to grams by multiplying by its molar mass:

mass of K2O = 0.051 mol * (94.20 g/mol) = 4.812 g

Therefore, according to the law of Conservation of Mass, 2 grams of potassium (K) reacts with 5 grams of oxygen (O) to produce 4.812 grams of potassium oxide (K2O).

Answer 2

2 grams of potassium (K) reacts with 5 grams of (O). According to the law of Conservation of Mass, how many grams of potassium oxide (K2O) will be produced?
A. 5 grams
B. 2 grams
C. 7 grams
D. 10 grams

Answer 3

To determine the mass of potassium oxide (K2O) produced, we need to calculate the molar masses of potassium (K) and oxygen (O).

The molar mass of K is 39.10 g/mol, and the molar mass of O is 16.00 g/mol.

Since we're given the mass of K and O in grams, we can convert these masses to moles by dividing each mass by its respective molar mass:

moles of K = 2 g / (39.10 g/mol) = 0.051 mol
moles of O = 5 g / (16.00 g/mol) = 0.312 mol

From the balanced chemical equation of the reaction between K and O:
2K + O2 -> 2K2O

We can see that for every 2 moles of K, the reaction produces 2 moles of K2O.

Since we have 0.051 mol of K, we'll have the same number of moles of K2O produced:

moles of K2O = 0.051 mol

Finally, we can convert the moles of K2O to grams by multiplying by its molar mass:

mass of K2O = 0.051 mol * (94.20 g/mol) = 4.812 g

Therefore, according to the law of Conservation of Mass, 2 grams of potassium (K) reacts with 5 grams of oxygen (O) to produce 4.812 grams of potassium oxide (K2O). Thus, none of the given options (A, B, C, or D) is the correct answer.

Answer 4

2 grams of potassium (K) reacts with 5 grams of (O). According to the law of Conservation of Mass, how many grams of potassium oxide (K2O) will be produced?

A. 5 grams

B. 2 grams

C. 7 grams

D. 10 grams

Answer 5

Since potassium (K) has a molar mass of 39.10 g/mol and oxygen (O) has a molar mass of 16.00 g/mol, we can begin by converting the masses of potassium (K) and oxygen (O) to moles:

moles of K = 2 g / (39.10 g/mol) ≈ 0.051 mol
moles of O = 5 g / (16.00 g/mol) ≈ 0.312 mol

According to the balanced chemical equation for the reaction between K and O:
2K + O2 -> 2K2O

We can see that for every 2 moles of K, the reaction produces 2 moles of K2O.

Since we have 0.051 mol of K, we'll have the same number of moles of K2O produced:

moles of K2O = 0.051 mol * 2 = 0.102 mol

Finally, we can convert the moles of K2O to grams by multiplying by its molar mass:

mass of K2O = 0.102 mol * (94.20 g/mol) ≈ 9.620 g

Therefore, according to the law of Conservation of Mass, 2 grams of potassium (K) reacts with 5 grams of oxygen (O) to produce approximately 9.620 grams of potassium oxide (K2O). Thus, the correct answer is not among the given options, A, B, C, or D.