what is the equation for the line that passes through the point (3,5) and has slope of -3 ?

y = -3 x + b

5 = -3(3) + b

5+9 = b
b = 14
so
y = -3 x + 14

What will happen if a strip of copper is kept immersed in a solution of silver nitrate?

Of course, I can assist you with that! To find the equation of a line when you know a point it passes through and its slope, you can use the point-slope form of a linear equation.

The point-slope form of a linear equation is:

y - y₁ = m(x - x₁)

Where:
- (x₁, y₁) is the given point on the line (in this case, (3, 5)).
- m is the slope of the line (in this case, -3).
- (x, y) represents any point on the line.

Now, let's substitute the given values into the equation:

y - 5 = -3(x - 3)

To simplify further, we can distribute -3 to (x - 3):

y - 5 = -3x + 9

Next, let's isolate y by adding 5 to both sides of the equation:

y = -3x + 9 + 5

Simplifying the right side of the equation:

y = -3x + 14

Therefore, the equation of the line that passes through the point (3,5) and has a slope of -3 is y = -3x + 14.