Asked by Brittany
finding the hypotenuse for triangles with only one measure of 7.8 m and two angles with degrees of 90 and 40. The picture is a right triangle with the right angle on the bottom left(labeled S). The hypotenuse goes from the top left(making angle Q with the line going up from S) to the bottom right, connecting with to make angle R. It looks like this, but connected and there is a bottom line. S is where the right angle is. Q-40degrees
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S | \ R
What is the length of hypotenuse in triangle QRS. Round to the nearest tenth.
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S | \ R
What is the length of hypotenuse in triangle QRS. Round to the nearest tenth.
Answers
Answered by
Reiny
You could have just said:
Triangle QSR is right-angled with
angleQ=40°, and angleS = 90°
From your description I cannot tell if QS=7.8 or SR = 7.8
I will guess that SR=7.8
then sin40° = 7.8/QR
QR = 7.8/sin40 = 12.135
if QS = 7.8
then cos40 = 7.8/QR
QR = 7.8/cos40 = 10.18
Triangle QSR is right-angled with
angleQ=40°, and angleS = 90°
From your description I cannot tell if QS=7.8 or SR = 7.8
I will guess that SR=7.8
then sin40° = 7.8/QR
QR = 7.8/sin40 = 12.135
if QS = 7.8
then cos40 = 7.8/QR
QR = 7.8/cos40 = 10.18
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