Asked by Robby
Square root of 14abc times the square root of 2ab
Answers
Answered by
Jai
note that we can rewrite the squareroot of a number by raising this number by 1/2
example, sqrt(5) = 5^(1/2)
therefore in the problem we have
sqrt(14abc) = (14abc)^(1/2) = [14^(1/2)][a^(1/2)][b^(1/2)][c^(1/2)]
sqrt(2ab) = (2ab)^(1/2) = [2^(1/2)][a^1/2][b^1/2]
now for the variables of the same base, we just add the exponents, and for constants we multiply the base and retain the exponent:
14^(1/2) * 2^(1/2) * a^(1/2 + 1/2) * b^(1/2 + 1/2) * c^(1/2)
28^(1/2) * a*b*c^(1/2)
2*sqrt(7) * ab* sqrt(c)
hope this helps~ :)
example, sqrt(5) = 5^(1/2)
therefore in the problem we have
sqrt(14abc) = (14abc)^(1/2) = [14^(1/2)][a^(1/2)][b^(1/2)][c^(1/2)]
sqrt(2ab) = (2ab)^(1/2) = [2^(1/2)][a^1/2][b^1/2]
now for the variables of the same base, we just add the exponents, and for constants we multiply the base and retain the exponent:
14^(1/2) * 2^(1/2) * a^(1/2 + 1/2) * b^(1/2 + 1/2) * c^(1/2)
28^(1/2) * a*b*c^(1/2)
2*sqrt(7) * ab* sqrt(c)
hope this helps~ :)
Answered by
Anonymous
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