Question
A 16000 kg sailboat experiences an eastward force of 17700 N due to tide pushing its hull while the wind pushes the sails with a force of 87500 N directed toward the northwest (45 degrees westward of North or 45 degrees northward of West). What is the magnitude of the resultant acceleration of the sailboat? Answer in units of m/s^2.
I'm not sure what equation to be using with this.
I'm not sure what equation to be using with this.
Answers
m = 16000kg.
X = hor = 17700 + 87500cos(90+45),
X = 17700 - 61872 = -44172N.
Y = ver = 87500sin(90+45),
Y = 61872N.
(Fr)^2 = X^2 + Y^2,
(Fr)^2 = (-44172)^2 + (61872)^2,
(Fr)^2 = 5,779,309,968,
Fr = 76022N. = Resultant force.
a = Fr / m = 76022 / 16000 = 4.75m/s^2.
X = hor = 17700 + 87500cos(90+45),
X = 17700 - 61872 = -44172N.
Y = ver = 87500sin(90+45),
Y = 61872N.
(Fr)^2 = X^2 + Y^2,
(Fr)^2 = (-44172)^2 + (61872)^2,
(Fr)^2 = 5,779,309,968,
Fr = 76022N. = Resultant force.
a = Fr / m = 76022 / 16000 = 4.75m/s^2.