Asked by please help(:
The sailboat in Question #1 returns to port in a straight line from its current position. The captain would like to know the total distance traveled (refer to distances in question #1).
1. What was the total distance traveled?
2. What was the final displacement?
1. 5.3+2.5+5.86= 13.66km
2.would i double 13.66?
1. What was the total distance traveled?
2. What was the final displacement?
1. 5.3+2.5+5.86= 13.66km
2.would i double 13.66?
Answers
Answered by
bobpursley
Not knowing the path, it is impossible for me to add anything.
Answered by
please help(:
oh wow im sorry! :)
A sailboat sails west from port for 5.3 km and experiences a shift in the wind direction. The wind blows the sailboat 2.5 km south. What is its displacement from its original position?
a^2+b^2=c^2
5.3^2+2.5^2=5.86^2SW
A sailboat sails west from port for 5.3 km and experiences a shift in the wind direction. The wind blows the sailboat 2.5 km south. What is its displacement from its original position?
a^2+b^2=c^2
5.3^2+2.5^2=5.86^2SW
Answered by
bobpursley
displacement= sqrt(5.3^2+2.5^2)
Now, the angle: Tan Theta= 2.5/5.3
so Theta = arctan(2.5/5.3) S of W
Now, the angle: Tan Theta= 2.5/5.3
so Theta = arctan(2.5/5.3) S of W
Answered by
please help(:
what is theta and arctan?!
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