Question

tan(x)=5 sin(x) for interval -π < x < π

Answer 1

tan(x)=sin(x)/cos(x)

sin(x)/cos(x)=5sin(x) Divide withsin(x)

1/cos(x)=5

1=5*cos(x) Divide with 5

cos(x)=1/5

cos(x)=0.2

OR

1/cos(x)=5

sec(x)=5

Answer 2

The only choices were A) 0, 1.571 B) -1.571, 0, 1.571 C) -1.369, 0, 1.369 D) 0, 1.369

Answer 3

tan(0)=0
sin(0)=0

tan(0)=5*sin(0)

0=0

arccos(0.2)=1.3694384 radians

tan(-alpha)= -tan(alpha)

sin(-alpha)= -sin(alpha)

tan(-1.3694384)=5 sin(-1.3694384)

Answer C) C) -1.369,0,1.369 is correct