A. (169 * 60) seconds * 3.53 meters/second = 357,942 meters distance which is 357,942 meters at 45 degrees S of E. That is 253,064 meters east and 253,064 meters south.
B. 3.53 - 2.00 = 1.53 m/s
C. is the same as A, 3.53 m/s SE. He just does not get to France
52. Bryan Allen pedaled a human-powered aircraft across the English Channel from the cliffs of Dover to Cap Gris-Nez on June 12, 1979. (a) He flew for 169 min at an average velocity of 3.53 m/s in a direction 45º south of east. What was his total displacement? (b) Allen encountered a headwind averaging 2.00 m/s almost precisely in the opposite direction of his motion relative to the Earth. What was his average velocity relative to the air? (c) What was his total displacement relative to the air mass?
2 answers
A)
Known
t = 169min
Va = 3.53m/s
Theta= 45°
x=?
169*60 = 10140
10140*3.53 = x
x= 35794.2m at 45° South of East
B)
3.53m/s is the velocity of Bryan 2 m/s is the velocity of the air. Ignoring air resistance we are comparing the velocity of that mass of air relative to the ground and Bryan relative to the ground to each other so instead of subtracting the two values we add them.
Degree is determined by reference angle
3.53+2
= 5.53m/s at 45° North of west
C)
Now just multiply by time
10140*5.53 = x
56074.2m
Known
t = 169min
Va = 3.53m/s
Theta= 45°
x=?
169*60 = 10140
10140*3.53 = x
x= 35794.2m at 45° South of East
B)
3.53m/s is the velocity of Bryan 2 m/s is the velocity of the air. Ignoring air resistance we are comparing the velocity of that mass of air relative to the ground and Bryan relative to the ground to each other so instead of subtracting the two values we add them.
Degree is determined by reference angle
3.53+2
= 5.53m/s at 45° North of west
C)
Now just multiply by time
10140*5.53 = x
56074.2m
0 answers