Question
A boat in calm seas travels 19 km east and 32 km south. Find the distance and direction of the trip, relative to the south. What is the distance? What is the direction?
I'm confused about how to solve this problem. Could someone show me the steps?
I'm confused about how to solve this problem. Could someone show me the steps?
Answers
Henry
X = hor = 19km.
Y = ver = -32km.
d^2 = X^2 + Y^2,
d^2 = (19)^2 + (-32)^2,
d^2 = 361 + 1024 = 1385,
d = 37.2km.
tanA = Y/X = -32/19 = -1.6842,
A = -59.3deg,CW=360 - 59.3 = 300.7deg CCW=300.7 - 270=30.7deg East of South.
Y = ver = -32km.
d^2 = X^2 + Y^2,
d^2 = (19)^2 + (-32)^2,
d^2 = 361 + 1024 = 1385,
d = 37.2km.
tanA = Y/X = -32/19 = -1.6842,
A = -59.3deg,CW=360 - 59.3 = 300.7deg CCW=300.7 - 270=30.7deg East of South.