Asked by josh
how do you separate the variable dy/dx=-xy^2, y(1)=-0.25
Answers
Answered by
bobpursley
dy/y^2=-xdx
-1/3 y^-3=-1/2 x^2 + constant
or 2y^3=3x^2+C solve for C at (1,-.25)
-1/3 y^-3=-1/2 x^2 + constant
or 2y^3=3x^2+C solve for C at (1,-.25)
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