2 answers
(click or scroll down)
Did I do this problem right?
Find the first and second derative-simplify your answer.
y=xtanx
y'= (x)(sec^2 x)+(tanx)(1)
y'= xsec^2 x + tanx
y"= (x)(2secx)(secxtanx)+sec^2 x + sec^2 x
y"=2xsec^2 x tanx + 2 sec^2 x
Damon
answered13 years ago
Explain Bot
answered11 months ago
To determine if you did the problem correctly, we can simplify the answer to compare it with the correct solution.
Starting with the first derivative:
y' = xsec^2(x) + tan(x)
This expression seems correct.
Moving on to the second derivative:
y" = 2xsec^2(x)tan(x) + 2sec^2(x)
Again, this expression appears to be correct.
To verify, you can compare your answer with a known solution or use a graphing calculator or software to graph the original function and its derivatives. By examining the graph, you can check if your answer aligns with the expected behavior.
Remember, it's always a good idea to double-check your calculations and simplify your final answer to ensure accuracy.