Asked by "anonymous"
can someone explain to me how to find the concentration of a liquid
Answers
Answered by
oops
i meant of an acid
Answered by
bobpursley
It depends on what you know, and what measure of concentration (there are dozens).
Answered by
oops
if you know the mL of the acid and the molarity and mL <milliliters> of the base
Answered by
bobpursley
it depends on what base, and what acid. YOu are dealing with concentraion in Normality. Read about that in your text.
Answered by
"anonymous"
please read the second oops i messed way up on my name bob
Answered by
Anonymous
HNO3 is the acid nitric acid magnesium hydroxide is the bace MgOH-
Answered by
Anonymous
do you want me to write the question
Answered by
Anonymous
are you still there bob or are you thinking
Answered by
bobpursley
Balance the equation. THis is a good first step in all reactions.
2HNO3 + Mg(OH)2>>Mg(NO3)2 + 2H2O
Now, if the acid is exaclty neutralized by half the moles of magnesium hydroxide.
So moles of acid used= concentration*volume=molarityacid*Va
Ma*Va=1/2 Mb*Vb and I assume you know the volumes of acid, and bas, and the molarity of the base.
2HNO3 + Mg(OH)2>>Mg(NO3)2 + 2H2O
Now, if the acid is exaclty neutralized by half the moles of magnesium hydroxide.
So moles of acid used= concentration*volume=molarityacid*Va
Ma*Va=1/2 Mb*Vb and I assume you know the volumes of acid, and bas, and the molarity of the base.
Answered by
Anonymous
does it make a difference if the base was titrated because i forgot to mention that
Answered by
Anonymous
the acid is titrated against the base i might have said that wrong last time
Answered by
Anonymous
thanks for your help if their isn't a difference i should be able to figure it out
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