Asked by Megan
Suppose you pour water into a container until it reaches a depth of 30.2 cm. Next, you carefully pour in a 14.8 cm thickness of olive oil so that it floats on top of the water. What is the pressure at the bottom of the container? Assume 1000 kg/m3 and 901 kg/m3 for the density of water and the oil, respectively.
Answers
Answered by
bobpursley
pressure=weightwater/area + weightoil/area
= densitywater*g*h*area/A +densityoil*g*h*area/A
= 1000*.302*9.8+901*.148*9.8 Pascals
= densitywater*g*h*area/A +densityoil*g*h*area/A
= 1000*.302*9.8+901*.148*9.8 Pascals
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