Asked by Megan
Piston 1 has a diameter of 0.524cm Piston 2 has a diameter of 5.64 cm. In the absence of friction, determine the force required on piston 1 necessary to support an object, m, with weight 1072 N. (Neglect the height difference between the bottom of the two pistons, and assume that the pistons are massless)
Answers
Answered by
bobpursley
The pressure is the same.
Force1/Area1=Force2/area2
figure the area of each (area=PI (diameter/2)^2)
Force1/Area1=Force2/area2
figure the area of each (area=PI (diameter/2)^2)
Answered by
Megan
Is the 1072N=F2?
Answered by
bobpursley
yes.
Answered by
Megan
So F1/2.15E-5=1072N/2.4E-3
F1= 2.15E-5*(1072/2.4E-3)
F1=9.63E10 N
I think I did this right but the answer comes up wrong when I submit it
F1= 2.15E-5*(1072/2.4E-3)
F1=9.63E10 N
I think I did this right but the answer comes up wrong when I submit it
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