Asked by Chris
The voltage of the power supply in a AC-DC coupled circuit is given by the function v(t) = 130sin5t + 18, where t is time, in seconds, and V is the voltage, in volts, at time t.
a) find the maxiumum and mimimum voltages and the times at which they occur
a) find the maxiumum and mimimum voltages and the times at which they occur
Answers
Answered by
Reiny
Always check if your previous post has been answered before posting the same question again.
http://www.jiskha.com/display.cgi?id=1299856899
The max/min can actually be calculated quite easily by just noting the property of the sine and cosine curves
No matter what the input, sinx has a max of +1 and a min of -1
so sin(5t) has a max of 1 and a min of -1
130sin(5t) has a max of 130 and a min of -130
130sin(5t) + 18 has a max of 148 and a min of -112
http://www.jiskha.com/display.cgi?id=1299856899
The max/min can actually be calculated quite easily by just noting the property of the sine and cosine curves
No matter what the input, sinx has a max of +1 and a min of -1
so sin(5t) has a max of 1 and a min of -1
130sin(5t) has a max of 130 and a min of -130
130sin(5t) + 18 has a max of 148 and a min of -112
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