What is the volume of 0.05-molar HCl that is required to neutralize 50 ml of a 0.10-molar Mg(OH)2 solution?

Answer 1

Mg(OH)2 + 2HCl ==> MgCl2 + 2H2O
mols Mg(OH)2 = M x L = ??
moles HCl = 2x that (Look at the coefficients in the balanced equation.)
M HCl = mols HCl/L HCl
Substitute and solve for L HCl.

Answer 2

0.05 L