Asked by Abe

What is the volume of 0.05-molar HCl that is required to neutralize 50 ml of a 0.10-molar Mg(OH)2 solution?
Answered by DrBob222
Mg(OH)2 + 2HCl ==> MgCl2 + 2H2O
mols Mg(OH)2 = M x L = ??
moles HCl = 2x that (Look at the coefficients in the balanced equation.)
M HCl = mols HCl/L HCl
Substitute and solve for L HCl.
Answered by andrea
0.05 L
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