You did te hard part. You just quit too soon. Here is the equation.
................BrO^- + HOH ==> HBrO + OH^-
I..............0.724.......................0.............0
C..............-x...........................x..............x
E...........0.724-x......................x..............x
You have written the Kb expression. Just substitute what each is and solve for x = (OH^-) and convert to pH
Need help!
Calculate the molar concentration of OH- in a 0.724M solution of hypobromite ion (BrO-; kB= 4.0 x 10^-6) what is the pH of this solution?
I got as far as kB = [OH-][HBrO]/[BrO-] please help me with the rest.
3 answers
Okay so I got. 4.0 x10^-6 = x^2/0.724m-x
Right??
Right??
Right but not m. If you want to put the unit in it would be M. Note that m stands for molality and M stands for molarity.
1 answer