D) 54
One vertex is x,y and the other is -x,y
y= 27 - x^2
A= 1/2 BxH
B = x - -x = 2x
H = 27 - x^2
A = 1/2 * 2x * (27 - x^2)
Take the derivative, find when the derivative is = 0 then plug that back in to get dimensions and solve for area.
The area of largest isosceles triangle that can be drawn with one vertex at the origin and with others on a line parallel to and above the x-axis and on the curve y=27-x^2 is....
A) 108
B) 27
C) 12 root 3
D) 54
E) 24 root 3
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