Asked by Alyssa
what is the area of a isosceles trapezoid with legs of 15 feet and bases of 10 feet and 28 feet?
Answers
Answered by
Steve
Draw a symmetric trapezoid. Mark the center of the bases
On the long base, each side is covered by half the short base, of length 5. That leaves a triangle on each end that has base 9, hypotenuse 15.
Looks like a 3-4-5 triangle to me, with height 12.
area = (b+B)h/2 = (10+28)*12/2 = 228
On the long base, each side is covered by half the short base, of length 5. That leaves a triangle on each end that has base 9, hypotenuse 15.
Looks like a 3-4-5 triangle to me, with height 12.
area = (b+B)h/2 = (10+28)*12/2 = 228
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