Asked by trisha
Element X has two natural isotopes:X-6 (6.015amu) and X-7 (7.016amu). calculate the atomic mass of element X given the abundance of X-7 is 92.5%.
a)12.5amu
b)6.50amu
c)6.09amu
d)6.52amu
e)6.94amu
a)12.5amu
b)6.50amu
c)6.09amu
d)6.52amu
e)6.94amu
Answers
Answered by
DrBob222
If X-7 is 92.5%, then X-6 must be 100-92.5 = 7.5%
Then 6.015(0.075) + 7.016(0.925) = ??
Then 6.015(0.075) + 7.016(0.925) = ??
Answered by
Arleena
6.4 aum
Answered by
Zoey
6.940925 amu
Can be rounded off to two decimal places as 6.94 amu
Can be rounded off to two decimal places as 6.94 amu
Answered by
Diamond
Element A has two isotopes. The first isotope is present 17.7% of the time and has a mass of 248.89. The second isotope has a mass of 206.58. Calculate the atomic mass of element A.
Answered by
Sophia
6.94amu
Answered by
Anonymous
Element X has two naturally occurring isotopes, X-6 which has a percent abundance of 92.41%, and X-7 which has an unknown abundance. Determine the percent abundance of X-7.
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