Asked by Junior

Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this is 33 days, while isotope B does this in 43 days. What is the approximate difference in the half-lives of the isotopes?
3 days
10 days
13 days
33 days
Answered by Steve
decaying to 10% takes

log0.10/log0.5 = 3.32 half-lives

So, A's half-life is 33/3.32 = 9.94 days
B's half-life is 43/3.32 = 12.95 days

Looks like (a) is the answer
Answered by Anonymous
33 dys
Answered by Anonymous
The two expressions below have the same value when rounded to the nearest hundredth.

mc013-1.jpg

What is the approximate value of mc013-2.jpg to the nearest hundredth?
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