Question

A mechanic jacks up the front of a car to an angle of 6.2° with the horizontal in order to change the front tires. The car is 2.91 m long and has a mass of 1100 kg. Gravitational force acts at the center of mass, which is located 1.02 m from the front end. The rear wheels are 0.41 from the back end. Calculate the magnitude of the torque exerted by the jack.

Answer 1

well, you have to consider the angle between the forces and the arm..


torque*(2.91-.41)sin(83.8)-1100*9.8*(2.91-1.02-.41)sin83.8=0

check that.