Asked by Mike
A mechanic jacks up the front of a car to an angle of 6.2° with the horizontal in order to change the front tires. The car is 2.91 m long and has a mass of 1100 kg. Gravitational force acts at the center of mass, which is located 1.02 m from the front end. The rear wheels are 0.41 from the back end. Calculate the magnitude of the torque exerted by the jack.
Answers
Answered by
bobpursley
well, you have to consider the angle between the forces and the arm..
torque*(2.91-.41)sin(83.8)-1100*9.8*(2.91-1.02-.41)sin83.8=0
check that.
torque*(2.91-.41)sin(83.8)-1100*9.8*(2.91-1.02-.41)sin83.8=0
check that.
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