Asked by Trace
                The length of the auditory canal in humans averages about 2.5 cm.  What is the second lowest 
standing wave frequency for a pipe of this length open at one end? Use 345 m/s for the speed of
sound.
I know that 4L=lambda, so lambda= 10cm.
I know that f=v/lambda, so f=3450 Hz.
But is that the lowest standing frequency? And how do I find the second lowest? Thanks
            
        standing wave frequency for a pipe of this length open at one end? Use 345 m/s for the speed of
sound.
I know that 4L=lambda, so lambda= 10cm.
I know that f=v/lambda, so f=3450 Hz.
But is that the lowest standing frequency? And how do I find the second lowest? Thanks
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