Asked by Josh
Sulfur dioxide gas reacts with hydrogen sulfide gas to produce elemental sulfur (S8) and water vapor. Predict the temperature range over which this reaction is spontaneous.
Answers
Answered by
DrBob222
I would do this.
Write the equation and balance it. It's a little tricky but here it is.
8SO2 + 16H2S ==> 3S8 + 16H2O
Look up delta Hf in tables (probably in yur text or you can find them on the web) and determine delta Hrxn.
deltaHrxn = (n*products of reaction)-(n*reactants)
Do the same thing for delta Srxn the same way.
Then delta G = delta Hrxn -TdeltaSrxn.
Plug in the numbers for deltaHrxn and deltaSrxn and determine T which will give a negative number for delta G.
Write the equation and balance it. It's a little tricky but here it is.
8SO2 + 16H2S ==> 3S8 + 16H2O
Look up delta Hf in tables (probably in yur text or you can find them on the web) and determine delta Hrxn.
deltaHrxn = (n*products of reaction)-(n*reactants)
Do the same thing for delta Srxn the same way.
Then delta G = delta Hrxn -TdeltaSrxn.
Plug in the numbers for deltaHrxn and deltaSrxn and determine T which will give a negative number for delta G.
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