Asked by JOhn Boku
Sulfur dioxide reacts with chlorine at 227 oC:
SO2(g) +Cl2(g) ↔ SO2Cl2(g)
Kp for this reaction is 5.1 x 10-2 atm-1. Initially, 1.00 g each of SO2 and Cl2 are placed in a 1.00 L reaction vessel. After 15 minutes, the concentration of SO2Cl2 is 45.5 μg/mL. You will determine if the system has reached equilibrium. First, what is Kc (in L/mol)? (A μg is 10-6 g.)
Next determine all initial concentrations. What is the initial sulfur dioxide concentration (in mol/L or M)?
Determine all concentrations after 15 minutes. What is the chlorine concentration?
What is Q after 15 minutes?
SO2(g) +Cl2(g) ↔ SO2Cl2(g)
Kp for this reaction is 5.1 x 10-2 atm-1. Initially, 1.00 g each of SO2 and Cl2 are placed in a 1.00 L reaction vessel. After 15 minutes, the concentration of SO2Cl2 is 45.5 μg/mL. You will determine if the system has reached equilibrium. First, what is Kc (in L/mol)? (A μg is 10-6 g.)
Next determine all initial concentrations. What is the initial sulfur dioxide concentration (in mol/L or M)?
Determine all concentrations after 15 minutes. What is the chlorine concentration?
What is Q after 15 minutes?
Answers
Answered by
DrBob222
Kp = Kc(RT)^delta n.
Solve for Kc.
Convert 1 g SO2 and Cl2 to mols/L
Calculate Qc and compare that with Kc.
Post your work if you get stuck.
Solve for Kc.
Convert 1 g SO2 and Cl2 to mols/L
Calculate Qc and compare that with Kc.
Post your work if you get stuck.
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