Asked by Zukii
Find the derivative of
F(z)=3+cos(2z-1)
F(z)=3+cos(2z-1)
Answers
Answered by
MathMate
Apply the chain rule:
F(z)=3+cos<i>(<b>2</b>z-1)</i>
F'(z)=-sin<i>(2z-1)</i>*<b>2</b>
=-2sin(2z-1)
F(z)=3+cos<i>(<b>2</b>z-1)</i>
F'(z)=-sin<i>(2z-1)</i>*<b>2</b>
=-2sin(2z-1)
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