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Please help!
Suppose that a 400 gram copper object (specific heat 0.092 cal/g/degrees Celsius) receives 900 cal. of heat. What is the temperature change? Explain your reasoning. Do not use algebra
Thanks!

Answers

Answered by bobpursley
900cal=400grams*.092cal/C*delatTemp

solve for DeltaTemp.

Do not use algebra? You have to be kidding. You could estimate it, 400x.1=40, and 400/40 is about 10C.

Answered by bobpursley
oops, the danger of estimated in the head.

900/40 is about 23C


Use algebra, and a calculator.
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