Asked by ally

Part 1
A 3.0 kg block is pushed 3.0 m at a constant
velocity up a vertical wall by a constant force
applied at an angle of 30.0
◦
with the horizontal, as shown in the figure.
The acceleration of gravity is 9.81 m/s2.
If the coefficient of kinetic friction between
the block and the wall is 0.30, find
a) the work done by the force on the block.
Answer in units of J.

Part 2
b) the work done by gravity on the block.
Answer in units of J.

Part 3
c) the magnitude of the normal force between
the block and the wall.
Answer in units of N.
Answered by Henry
1. Fb = 3kg * 9.8N/kg = 29.4N @ 30deg =
Force of block.

Fp = 29.4sin30 = 14.7N = Force parallel to plane acting downward.

Fv = 29.4cos30 = 8.82N = Force perpendicular to plane acting downward.

Ff = u*Fv = 0.3 * 8.82 = 2.65N. = Force of friction.

Fap - Fp - Ff = 0,
Fap = Fp + Ff = 14.7 + 2.65 = 17.35N.
= Force applied parallel to plane
acting upward.

W = Fap * d = 17.35 * 3 = 52.05J.
Answered by Taylor
what does that mean Henry?? We trying to cheat, not learn the whole lesson homie.
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