Asked by Abigail
Can someone please explain me how to do this problem?
A 25mL solution of 0.5 M NaOH is titrated until neutralization into a 50mL sample of HCl. What was the concentration of the HCl?
A 25mL solution of 0.5 M NaOH is titrated until neutralization into a 50mL sample of HCl. What was the concentration of the HCl?
Answers
Answered by
Abigail
I just got the answer... it's 0.25 M right?
Answered by
DrBob222
mL x M = mL x M
25 mL x 0.5M = 50 mL x M
M HCl = (25 x 0.5/50) = 0.25M is right although the number of significant figures is not right IF 0.5, 25, and 50 are the actual numbers. I suspect you may have omitted the zeros on 0.50 etc.
25 mL x 0.5M = 50 mL x M
M HCl = (25 x 0.5/50) = 0.25M is right although the number of significant figures is not right IF 0.5, 25, and 50 are the actual numbers. I suspect you may have omitted the zeros on 0.50 etc.
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