Question

A magician pulls a tablecloth from under a 200 g mug located 30.0 cm from the edge of the cloth. The cloth exerts a friction force of 0.105 N on the mug, and the cloth is pulled with a constant acceleration of 3.50 m/s2. How far does the mug move relative to the horizontal tabletop before the cloth is completely out from under it? Note that the cloth must move more than 30 cm relative to the tabletop during the process.

Answer 1

consider the mug: F=ma you know F, you know the time of force (time=distance/velocitycloth), so

Force*time=massmug*velocitymug

from that,you caculate the averagevelocity of the mug (1/2 velocityfinalmug), then distance=avgvelocity*time

Answer 2

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Answer 3

llml;m