Asked by Emily Grossman
How much work must be done to stop a 1250 kg car traveling at 105 km/h?
Answers
Answered by
c:
Work is Force multiplied by distance.
1250*105=?
Your answer will be in watts.
1250*105=?
Your answer will be in watts.
Answered by
Emily Grossman
So then you have to convert it to joules?
Answered by
lauren
131,250
Answered by
Alan
531684.027J
Answered by
samuel
you will first of all conevert km/h to m/s which is 105 multiply 1000 then divide by 3600= 29.7.
use the formula f= ma.
1250 multiply by 9.8=12250
then use formula for work
w=f multiply by distance
w=12250 multiply by 29.7=363825J.
use the formula f= ma.
1250 multiply by 9.8=12250
then use formula for work
w=f multiply by distance
w=12250 multiply by 29.7=363825J.
Answered by
Anonymous
5.3xă10ă^5 J
Answered by
bradford
physics sucks
Answered by
anonymous
-531685J
Answered by
Jennie Kim
First convert km/h to m/s because we need the answer to be J, which is Kg/m^2/s^2
105km/h=29.2 m/s (the rule is, to go from km/h to m/s is divide by 3.6)
W=1/2mv^2
W=(0.5)(1250)(29.2)^2
W=531684J
AND, because the work is being done to slow something down, it is negative.
So the answer is -531684J. (the comment above me is correct, I just wanted to provide an explanation for anyone who wanted to know how he/she above me got to the correct answer)
105km/h=29.2 m/s (the rule is, to go from km/h to m/s is divide by 3.6)
W=1/2mv^2
W=(0.5)(1250)(29.2)^2
W=531684J
AND, because the work is being done to slow something down, it is negative.
So the answer is -531684J. (the comment above me is correct, I just wanted to provide an explanation for anyone who wanted to know how he/she above me got to the correct answer)