Part a is a stoichiometry problem. Just follow the steps at this link.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Part b.
The equation is
CuSO4 + 2NaOH ==> Cu(OH)2 + Na2SO4
Make an ICE chart. The equilibrium conditions will be moles/L. Don't forget that the final volume is 147.08 mL. Also, the (CU^+2) will be determined from the solubility product of Cu(OH)2.
Post your work if you get stuck.
Some solid copper(II) sulfate is dissolved in sufficient water to make 100.0 mL of solution. Enough of a sodium hydroxide solution of concentration 0.1500 mol/L is added just to react with all of the first solution, with none left over. This turns out to be a volume of 47.08 mL. (a)calculate the mass of the solid copper(II) sulfate. (b)calculate the end concentrations of all dissolved ions.
1 answer
1 answer