Fe(s) + CuSO4(aq) ==> FeSO4(aq) + Cu(s)
balanced as is.
When,heated solid iron reacts with solution of copper(II)sulfate to yield aqueous iron(II)sulfate and solid copper metal?
balanced as is.
Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
Let's balance the equation step by step:
Step 1: Balance the metals
In this reaction, we have one iron atom on the left side and one copper atom on the right side. Therefore, the balanced equation becomes:
Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
Step 2: Balance the non-metals
Next, we balance the non-metal atoms, namely sulfur and oxygen, within the sulfate ions:
Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
Step 3: Check and balance the charges
Lastly, we check the charges of the ions involved. In this equation, everything is neutral, so no adjustments are necessary.
The final balanced equation is:
Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)