Asked by Tiffany

At a certain temperature, Kc = 33 for the reaction:

H2(g) + I2(g) 2HI(g)

Assume that the initial concentrations of both H2 and I2 are 6.00 x 10-3 mol/L. Find the concentration of each reactant and product at equilibrium.

Answers

Answered by DrBob222
You need to insert the arrow to know the difference between products and reactants. You have the equation, set up an ICE chart.
....................H2 + I2 ==> 2HI
...initial........0.006..0.006...0
change..............-x....-x.....2x
equilibrium.....0.006-x...0.006-x...2x

Now substitute into the Kc expression of
Kc = 0.33 = (HI)^2/(H2)(I2)
Solve for x and calculate each of the final concns. Post your work if you get stuck.
Answered by ina
X=1.97406×10 power of -3 .then what is the reactant and product of equilibrium .can't understand actually .
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions