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If n is a positive integer, find the limit as n approaches +∞ of 1/n(sin (π/n) + sin (2π)/n + ... + sin (nπ)/n)
14 years ago

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If n is a positive integer, find the limit as n approaches +∞ of 1/n(sin (π/n) + sin (2π)/n + ... + sin (nπ)/n)

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