Asked by Emily Grossman
How do you solve this problem?
A ball on the end of a string is revolved at a uniform rate in a vertical circle radius of 72.0 cm, as shown in figure. If its speed is 4.00m/s and its mass is .300 kg. Calculate the tension in the string when the ball is a) at the top of the path, and b). when it's at the bottom?
A ball on the end of a string is revolved at a uniform rate in a vertical circle radius of 72.0 cm, as shown in figure. If its speed is 4.00m/s and its mass is .300 kg. Calculate the tension in the string when the ball is a) at the top of the path, and b). when it's at the bottom?
Answers
Answered by
drwls
a) Mg + T = MV^2/R
T = M(V^2/R -g)
b) T - Mg = MV^2/R
T = M(V^2/R + g)
T is the tension that you want to compute.
Make sure R is in meters when you do the calculation. The force will be in Newtons.
T = M(V^2/R -g)
b) T - Mg = MV^2/R
T = M(V^2/R + g)
T is the tension that you want to compute.
Make sure R is in meters when you do the calculation. The force will be in Newtons.
Answered by
Emily Grossman
Can you like work the problem out so i can see how it is done?
Answered by
Emily Grossman
what is the V in this case? That's what throwing me off..
Answered by
bobpursley
V is velocity, given as 4m/s
Answered by
Emily Grossman
Okay, I worked them out, but I am not getting the answer they should be. Like a) i am getting as what should be the answer as b. So, i don't if someone could work them out or tell me maybe what doing wrong. Thanks!
Answered by
drwls
If the answers to a and b answers are interchanged, your book may be wrong.
All you have to do is use the formulas provided, using these variables:
V = 4.0 m/s
M = 0.3 kg
g = 9.8 m/s^2
R = 0.72 m
All you have to do is use the formulas provided, using these variables:
V = 4.0 m/s
M = 0.3 kg
g = 9.8 m/s^2
R = 0.72 m
Answered by
Emily Grossman
Okay, so for a) get 3.13 and b). get 16.5?
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