Asked by ashley
                How do I solve this problem? What steps do I need to do to solve this question? It asked  on paper, "You place a piece of paper on a balance and find that its mass is 0.63 g. You add a lump of NaOH to the paper and get a mass of 22.21 g. How Much NaOH do you have on the balance, in grams, milligrams, micrograms and kilograms?"
How do I solve milligrams, micro and kilogram using 22.21 grams and 0.63? do I subtract??
            
        How do I solve milligrams, micro and kilogram using 22.21 grams and 0.63? do I subtract??
Answers
                    Answered by
            ashley
            
    Seriously do i just subtract or what? what am i suppose to do?
someone answer grams but it wasn't explain how they got the answer
    
someone answer grams but it wasn't explain how they got the answer
                    Answered by
            DrBob222
            
    Yes, subtract
22.21 g = mass paper + mass NaOH
- 0.63 g = mass paper
-----------------------------------
21.58 g = mass NaOH
(You will note that 22.21-0.62 is the 21.58 g. When you subtract mass paper from mass paper you get nothing. When you subtract mass NaOH - zero you get mass NaOH. So the next lined reads 21.58 g = mass NaOH.
Now convert 21.58 g to the other units. I'll do one for you; i.e., from grams
to kg. In your text or notes you will find that there are 1000 g in 1 kg so
21.58 g x (1 kg/1000 g) = 0.02158 kg
I shall be happy to check your other calculations. This is not rocket science so don't be discouraged.
    
22.21 g = mass paper + mass NaOH
- 0.63 g = mass paper
-----------------------------------
21.58 g = mass NaOH
(You will note that 22.21-0.62 is the 21.58 g. When you subtract mass paper from mass paper you get nothing. When you subtract mass NaOH - zero you get mass NaOH. So the next lined reads 21.58 g = mass NaOH.
Now convert 21.58 g to the other units. I'll do one for you; i.e., from grams
to kg. In your text or notes you will find that there are 1000 g in 1 kg so
21.58 g x (1 kg/1000 g) = 0.02158 kg
I shall be happy to check your other calculations. This is not rocket science so don't be discouraged.
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