Asked by CR
A string under a tension of 48 N is used to whirl a rock in a horizontal circle of radius 2.4 m at a speed of 18.48 m/s. The string is pulled in, and the speed of the rock increases.
When the string is 1.076 m long and the speed of the rock is 49.4 m/s, the string breaks. What is the breaking strength of the string?
Answer in units of N.
When the string is 1.076 m long and the speed of the rock is 49.4 m/s, the string breaks. What is the breaking strength of the string?
Answer in units of N.
Answers
Answered by
drwls
The string tension is proportional to V^2/R, the centripetal acceleration.
[V^2/R]initial = 142.3 m/s^2
[V^2/R]final = 2268 m/s^2
The breaking strength is therefore
48*(2268/142.3) = ___ N
[V^2/R]initial = 142.3 m/s^2
[V^2/R]final = 2268 m/s^2
The breaking strength is therefore
48*(2268/142.3) = ___ N
Answered by
Joy
765.03
Answered by
Kate
THAT DIDNT HELP AT ALL ARGHHHHHHHH! JUST GIVE US THE ANSWER ALREADY
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