Asked by Emily
find the derivative of 3/ln(3z)
Answers
Answered by
bobpursley
y= 3(ln(3z))^-1
y'= -3(ln(3z)^-2 * 1/3z= -1/z(ln(z))^2
check that
y'= -3(ln(3z)^-2 * 1/3z= -1/z(ln(z))^2
check that
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