Asked by Johnathon

A tennis ball of mass m = 0.065 kg and speed v = 35 m/s strikes a wall at a 45° angle and rebounds with the same speed at 45° (see figure). What is the impulse given to the wall?
Magnitude
Answered by bobpursley
well, the impulse was given perpendicular to the wall. THe compoent of velocity perpendicular is 35*.707, so change velocity is twice that.

impulse= 2*35*.707 kg m/s