Asked by Anonymous

A tennis ball of mass m = 0.065 kg and speed v = 25 m/s strikes a wall at a 45° angle and rebounds with the same speed at 45° (Fig. 7-29). What is the impulse given the wall?

I started out with finding the momentum and doubling it to get the impulse on the wall but that isn't the right answer. What equation do I need to start this one? Does it have to do with the angles they are giving me?

Answers

Answered by bobpursley
No, that is not right. Only the normal component doubles.

Vfinalnormal =25*.707*2

Force*time=m*vfinalnormal
You have to only dealt with what changed, the momentum normal, and the implulse norma.

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