Asked by Anonymous

Water drops over 49 m high Niagara Falls at the rate of 6.0 106 kg/s. If all the energy of the falling water could be harnessed by a hydroelectric power plant, what would be the plant's power output

hey can you please do this one step at a time, i couldn't understand the previous equation

Answers

Answered by bobpursley
power= work/time= mgh/time= m/time *gh

= 6E6kg/s * 9.8N/kg * 49m

but N-m/s is a watt
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