Asked by mNoellb
As a woman walks, her entire weight is momentarily supported on the heel of one shoe. Calculate the pressure exerted on the floor by a high-heel shoe worn by a 50-kg woman if the heel has an area of 2.0cm^2. Express the pressure in newtons per square meter and atmospheres.
I am using the formula :
P= F/A => F=mg A= 3.14(r^2)
M-50 kg
g=9.8 m/sec^2
r^2- (2cm^2)^2
I have the answer in my book so I know I'm not getting the formula right and I don't know why. Can someone please help me.
Thank you!
I am using the formula :
P= F/A => F=mg A= 3.14(r^2)
M-50 kg
g=9.8 m/sec^2
r^2- (2cm^2)^2
I have the answer in my book so I know I'm not getting the formula right and I don't know why. Can someone please help me.
Thank you!
Answers
Answered by
drwls
Heel pressure = (weight)/(heel area)
The heel area must be expressed as 2*10^-4 m^2. The heel pressure is M*g/2*10^-4 m^2
The dimensions wil be Pascals if M is in kg and g is 9.8 m/s^2.
The heel area must be expressed as 2*10^-4 m^2. The heel pressure is M*g/2*10^-4 m^2
The dimensions wil be Pascals if M is in kg and g is 9.8 m/s^2.
Answered by
mNoellb
I get it now! lol Thank you!
(50 kg)(9.8 m/sec^2)
____________________
(2.0m *10^-4)
=>
2.45 * 10^6 N-m or Pa
(50 kg)(9.8 m/sec^2)
____________________
(2.0m *10^-4)
=>
2.45 * 10^6 N-m or Pa
Answered by
hi
98
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.