Asked by steve
a woman 1.5 tall walks at a rate of 1.2m/s directly away from the street light that is 6m above the street. At what rate is her shadow changing?
Answers
Answered by
Steve
Using similar triangles, if the shadow's length is s and the woman is x away from the light,
s/1.5 = (x+s)/6
That should help, eh?
s/1.5 = (x+s)/6
That should help, eh?
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