Question

A projectile is fired in such a way that its horizontal range is equal to 8.5 times its maximum height. What is the angle of projection?
From h = V^2(sin2µ)/2g and d = V^2(sin^2µ)/g:

d = V^2(sin2µ)/32 = 8.5V^2(sin^2µ)/32 yielding µ = 25.2º.
A projectile is fired in such a way that its horizontal range is equal to 2.5 times its maximum height. What is the angle of projection?

Related Questions

a projectile is fired with an initial speed of 53 m/s. Find the angle of projection such that the ma... A projectile is fired such that its horizontal range is equal to 2.5 times its maximum height. Find... A projectile is fired in such a way that its horizontal range is equal to three times its maximum he...