a golf ball is hit off a tee witha speed of 50m/s at an angle of 37 degrees above the horizontal. At what two values of x (horizontal distance from the tee) will the ball be 25m above the ground?

Answer 1

Multiply the horizonatal velocity component, 50 cos37 = 39.93 m/s, by the two times T that the vertical altitude is 25 m.

Get those times by solving the quadratic equation

H = 50 sin37 *T -4.9 T^2 = 25 m