Asked by Anonymous
After a golf ball is hit it takes off with an initial speed of 22.0 m/s and at an angle of 38.0° with respect to the horizontal. The golf field is flat and horizontal. Neglecting air resistance how far will the golf ball fly?
Answers
Answered by
bobpursley
find time in air:
hf=hi+22Sin38*t-4.9t^2
solve for time in the air, t, when height final hf is zero.
horizontal: distance=2cos38 * timeinair.
hf=hi+22Sin38*t-4.9t^2
solve for time in the air, t, when height final hf is zero.
horizontal: distance=2cos38 * timeinair.
Answered by
Anonymous
How high will the golf ball rise?
im not sure how to do that one
im not sure how to do that one
Answered by
bobpursley
Max altitude?
1) What is altitude at TimeinAir/2 ?
hf=hi+22Sin38*t-4.9(t/2)^2
1) What is altitude at TimeinAir/2 ?
hf=hi+22Sin38*t-4.9(t/2)^2
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